1.

In a `Delta ABC` line DE is parallel to BC. Prove that `(AD)/(AB) = (DE)/(BC) = (AD)/ (AC)`

Answer» As, `DE` and `BC` are parallel,
`:. /_ABC = /_ADE and /_ACB = /_AED`
Now, in `Delta ADE` and `Delta ABC`,
`/_DAE = /_BAC` (Common angle)
`/_ABC = /_ADE`
` /_ACB = /_AED`
From Angle-Angle-Angle similarity rule,
`Delta ADE ~= Delta ABC`
`:. (AD)/(AB) = (DE)/(BC) = (AE)/(AC)`


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