1.

In a double experiment, the distance between the slit is 1 mm and screen is 25 cm away from the slits. The wavelength of light is `6000Å`. The width of the fringe on the screen isA. `0.15 mm`B. `2.24 mm`C. `0.30` mmD. `0.12 mm`

Answer» Correct Answer - A
`d=1 mm, D=25 cm, lambda 6000A^(@), beta = ?`
`beta =(D)/(d) lambda`
`=(25xx10^(-2)xx6xx10^(-7))/(1xx10^(-3))`
`=150xx10^(-6) m`
`0.15 m`


Discussion

No Comment Found

Related InterviewSolutions