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In a double experiment, the distance between the slit is 1 mm and screen is 25 cm away from the slits. The wavelength of light is `6000Å`. The width of the fringe on the screen isA. `0.15 mm`B. `2.24 mm`C. `0.30` mmD. `0.12 mm` |
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Answer» Correct Answer - A `d=1 mm, D=25 cm, lambda 6000A^(@), beta = ?` `beta =(D)/(d) lambda` `=(25xx10^(-2)xx6xx10^(-7))/(1xx10^(-3))` `=150xx10^(-6) m` `0.15 m` |
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