InterviewSolution
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InterviewSolution
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In a double slit experiment the angular width of a fringe is found to be `0.2^(@)` on a screen placed I m away. The wavelength of light used in 600 nm. What will be the angular width of the fringe if the entire experimental apparatus is immersed in water ? Take refractive index of water to be `4//3`. |
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Answer» Distance of the screen from the slits ,D=1m wavelength of light used ,`lamda_(1) =600 nm` Angular width of the fringe in ` air thera_(1) = 0.2 ^(@)` Angular of the fringe in water `= theta_(2)` Refractive index of water `mu =(4)/(3)` Refactive index is related to angular width as : `mu =(thata_(1))/(thera_(2))` `theta _(2) =(3)/(4)theta_(1)` `=(3)/(4) xx0.2 =0.15 ` therefore , the angluar width of the fringe in water will reduce to `0.15 ^(@)` |
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