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In a fee lattice structure, what is the effective number of atoms? (a) 4 (b) 3 (c) 2 (d) 1. |
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Answer» Correct answer is (a) 4 N = \(\frac{N_c}{8}\) + \(\frac{N_F}{2}\) = \(\frac{8}{8}\) + \(\frac{6}{2}\) = 4. |
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