1.

In a flight 6000km, an aircraft was slowed down due to badalt was slowed down due to bad weather. Its averagespeed for the trip was reduced by 400 km/hr and the time of thgis reduced by 400 km/hr and the time of flight increased by30 minutes. Find the duration of flight.

Answer»

Let the original speed of the aircraft be 'x' km/hrDecreased speed of the aircraft = (x - 400) km/hrTime = Distance/SpeedOriginal duration of the flight = (6000 / x) hrsDuration of the flight with decreased speed = (6000 / x-400) hrsDifference of time = 30 min = 1/2 hrs⇒ (6000 / x-400) - (6000 / x) = 1/2⇒ (6000x - 6000x + 2400000) / x(x - 400) = 1/2⇒ x^2- 400x = 4800000⇒ x^2- 400x - 4800000 = 0⇒ (x - 2400)(x + 2000) = 0⇒ x = 2400 or -2000Positive value of x is 2400.Therefore original speed of the aircraft is 2400 km/hr.Original duration of the aircraft = 6000/2400 = 2.5 hrs.



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