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| 1. |
In a Frank-Hertz experiment,an electron of energy `5.6eV` passes through mercury vapour and emerges with an energy `0.7eV`. The minimum wavelength of photons emitted by mercury atoms is close to :A. 1700 nmB. 2020 nmC. 220 nmD. 250 nm |
| Answer» Correct Answer - A | |