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In a fuel cell, hydrogen and oxygen react to produce electricity. In process, hydrogen gas is oxidized at the anode and oxygen at the cathode. If `67.2L` of `H_(2)` at `STP` reacts in `15mi n` , what is the average current produced ? If the entire current is used for electro`-` deposition of copper from copper `(II)` solution, how many grams of copper will be deposited ? Anode reaction `: H_(2)=2overset(c-)(O)Hrarr2H_(2)O+2e^(-)` Cathode reaction `:O_(2)+2H_(2)O+2e^(-) rarr 4overset(c-)(O)H` |
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Answer» Correct Answer - `190.5g` Moles of `H_(2)` reacting `=(67.2)/(22.4)=3` `:. `Equivalent of `H_(2)` used `=3xx2=6` Now, `(W)/(E_(w))=(It)/(96500)` `:. 6=(Ixx15xx60)/(96500)` `:.I=643.33A` Also, equivalent of `H_(2)=` equivalent of `Cu` formed `:. ` Equivalent of `Cu` deposited `=6` `:. W_(Cu)=6xx(63.5)/(2)=190.5g` Thus, weight of `Cu` deposited `=190.5g` |
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