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In a full wave junction diode rectifier, the input ac voltage has rms value of 10V. The transformer used is a step up one having transformation ratio 1:2. Calculate the DC voltage in the rectified output. |
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Answer» Here, Input rms voltage, Vrms = 10 V ∴ Peak value of input voltage, E0 = √2. Vrms = √2 ×10 = 14.14 V Since, the transformer is a step-up transformer, having transformation ratio 1:2, the maximum value of output voltage of the transformer applied to the diodes will be : E'0 = 2 × E0 = 2 × 14.14 = 28.28 V ∴ DC voltage = \(\frac{2E'_0}{\pi}\) = \(\frac{2\times 28.28\times 7}{22}\) = 18 V. |
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