InterviewSolution
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InterviewSolution
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. In A(g)3A (g) reaction, the initialconcentration of A, is "a" mol L-1 If x is degree ofdissociation of A,. The total number of moles atequilibrium will be:ax3a- ax(4) of these |
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Answer» The reaction is A3 <----> 3A ..... initially the no. of moles/lt of A is "a".given x is the degree of dissociation mean xa moles have dissociated. so A₃ <=> 3A at equilibrium (a)(1-x) <=> 3ax now total no..moles are a-ax +3ax = a+2ax. so , option D. is correct. also you can check that if the dissociation is 100% (x =1) that if all the A₃ dissociates to 3A , then total no. of moles will be 3a. so on putting x = 1 in (a+2ax) we get 3a. that is true. |
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