In a galvanometer 15% of the total current in the circuit passes through it. If the resistance of the galvanometer is G, then find out the shunt resistance S that is connected to the galvanometer.(a) \(\frac {17G}{3}\)(b) \(\frac {16G}{3}\)(c) \(\frac {5G}{17}\)(d) \(\frac {3G}{17}\)I had been asked this question during an interview for a job.I would like to ask this question from Moving Coil Galvanometer topic in section Moving Charges and Magnetism of Physics – Class 12

In a galvanometer 15% of the total current in the circuit passes throu

1.	In a galvanometer 15% of the total current in the circuit passes through it. If the resistance of the galvanometer is G, then find out the shunt resistance S that is connected to the galvanometer.(a) \(\frac {17G}{3}\)(b) \(\frac {16G}{3}\)(c) \(\frac {5G}{17}\)(d) \(\frac {3G}{17}\)I had been asked this question during an interview for a job.I would like to ask this question from Moving Coil Galvanometer topic in section Moving Charges and Magnetism of Physics – Class 12
Answer» Correct option is (d) \(\FRAC {3G}{17}\) Explanation: Ig = \((\frac {15}{100})\) × I S = Ig × \(\frac {G}{I – I_g}\) S = \( ( \frac {15}{100})\) × I × \(\frac {G}{(I – 15 \times \frac {I}{100})}\) S = [0.15 × \( \frac {I}{(I – 0.15 \times I)} \) ] × G S = [0.15 × \( \frac {I}{0.85 \times I} \) ] × G S = \( \frac {15}{85} \) × G S = \( \frac {3G}{17} \) THEREFORE, the shunt resistance required is \( \frac {3G}{17} \).

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