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In a garden there are two plants. One plant is \( 44 \mathrm{~cm} \) tall and the other is \( 80 \mathrm{~cm} \) tall. The first. plant grows \( 3 \mathrm{~cm} \) in every 2 months and the second \( 5 \mathrm{~cm} \) in every 6 months. The number of months after which the two plants will have equal height is . |
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Answer» First plant height = 44 cm and it grows 3 cm in every 2 months. \(\therefore\) Common difference = 3/2 After 1st month plant height = 44 + 3/2 = (88 + 3)/2 = 91/2 After nth month first plant height = 91/2 + (n - 1)3/2. Second plant height = 80 cm and it grows 5cm in every 6 months. \(\therefore\) Common difference = 5/6 After 1st month plant height = 80 + 5/6 = 485/6 After nth month second plant height = 485/6 + (n - 1)5/6 Let both plants have equal height after n month. Therefore, 91/2 + (n -1) 3/2 = 485/6 + (n - 1) 5/6 ⇒ (n -1) (3/2 - 5/6) = 485/6 - 91/2 = (485-273)/6 = 212/6 ⇒ (n –1)=212/6 x 6/(9 - 5) = 212/4 = 53 ⇒ n = 53 + 1 = 54 \(\therefore\) After 54th month both plants will have equal height. |
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