In a gas phase reaction, 50 kg of nitrogen and 10 g of hydrogen are mixed to produce ammonia. Identify the limiting reagent. Calculate the maximum amount of ammonia produced.

In a gas phase reaction, 50 kg of nitrogen and 10 g of hydrogen are mi

1.	In a gas phase reaction, 50 kg of nitrogen and 10 g of hydrogen are mixed to produce ammonia. Identify the limiting reagent. Calculate the maximum amount of ammonia produced.
Answer» Solution :The gaseous PHASE CHEMICAL equation for the PRODUCTION of ammonia is given as `N_(2)+3H_(2)rarr2NH_(3)` 1 mole of `N_(2)-=` moles of `H_(2)` `"28 kg of "N_(2)=(2XX3)" kg of "H_(2)` `"46.67 kg of "N_(2)="10 kg of "H_(2)` `"50 kg of "N_(2)="10.71 kg of "H_(2)` Hence, hydrogen is the limiting reagent, `"3 moles of "H_(2)="2 moles of "NH_(3)` `(3xx2)" kg of "H_(2)=(2xx17)" kg of "NH_(3)` `"10 kg of "H_(2)=?` Maximum amount of ammonia produced is `=(2xx17xx10)/(3xx2)=56.6kg`