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In a given process of an ideal gas, dW = 0 and dQ < 0. Then for the gas (a) the temperature will decrease, (b) the volume will increase (c) the pressure will remain constant (d) the temperature will increase |
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Answer» Correct answer is (a) From first law of thermodynamics dQ = dU + dW dQ = dU (if dW = 0) Since, dQ < 0 dU < 0 or Ufinal < Uinitial Hence, temperature will decrease. |
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