InterviewSolution
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InterviewSolution
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In a `GP` if the `(m+n)th` term is `p` and `(m-n)th` term is `q` then `mth` term isA. `p((q)/(p))^((m)/(2n))`B. `sqrt(pq)`C. `sqrt((p)/(q))`D. None of these |
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Answer» Let a be the first term and r be the common ratio, then `t_(m+n)=p implies ar^(m+n-1)=p " .....(i)"` `t_(m-n)=q implies ar^(m-n-1)=q " .....(ii)"` From Eqs. (i) and (ii), we get `ar^(m+n-1)xxar^(m-n-1)=pxxq` ` implies a^(2)r^(2m-2)=pq implies ar^(m-1)=sqrt(pq)` ` implies t_(m)=sqrt(pq)` Hence, (b) is the correct answer. |
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