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An infinite GP has first term `x`and sum 5, then `x`belongs to(2004, 1M)`x |
Answer» Correct Answer - C We know that, the sum of infinite terms of GP is `S_(oo) = {((alpha)/(1 -r)","|r| lt1),(oo"," |r| ge 1):}` `:. S_(oo) = (x)/(1 -r) = 5 " " [|r| lt 1]` or `1 - r = (x)/(5)` `rArr r = (5 -x)/(5)` exists only when `|r| lt1` i.e. `-1 lt (5 -x)/(5) lt 1` or `10 lt - x lt 0` `rArr 0 lt x lt 10` |
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