In a hot water heating system, there is a cylindrical pipe of length 2

1.	In a hot water heating system, there is a cylindrical pipe of length 28 m and diameter 5 cm. Find the total radiating surface in the system. [ Assume π = 22/7 ]
Answer» Height (h) of cylindrical pipe = Length of cylindrical pipe = 28 m Radius (r) of circular end of pipe = 5/2 = 2.5 cm = 0.025m CSA of cylindrical pipe = 2πrh = ( 2 x 22/7 x 0.025 x 28) m² = 4.4 m² The area of the radiating surface of the system is 4.4 m².

In a hot water heating system, there is a cylindrical pipe of length 28 m and diameter 5 cm. Find the total radiating surface in the system. [ Assume π = 22/7 ]

Answer»

Height (h) of cylindrical pipe = Length of cylindrical pipe = 28 m

Radius (r) of circular end of pipe = 5/2 = 2.5 cm = 0.025m

CSA of cylindrical pipe = 2πrh

= ( 2 x 22/7 x 0.025 x 28) m²

= 4.4 m²

The area of the radiating surface of the system is 4.4 m².