In a hydraulic lift, the area of smaller piston is 5 cm^2. The weight raised by larger piston is 900 kgf, if a force of 150 kg fis applied on smaller piston. Calculate the area of larger piston.

In a hydraulic lift, the area of smaller piston is 5 cm^2. The weight

1.	In a hydraulic lift, the area of smaller piston is 5 cm^2. The weight raised by larger piston is 900 kgf, if a force of 150 kg fis applied on smaller piston. Calculate the area of larger piston.
Answer» Solution :`a=5 CM^(2) =5 xx 10^(-4) m^(2)` f=150kgf `=150 xx 9.8 N` `F=900 xx 9.8 N` As `f/a=F/A` `(150 xx 9.8)/(5 xx 10^(-4)) =(900) xx 9.8)/(A))` Solving we get `A=30 xx 10^(-4) m^(2)`