In a hydraulic lift, the area of smaller piston is 5 cm^2. The weight raised by larger piston is 900 kgf, if a force of 150 kg fis applied on smaller piston. Calculate the area of larger piston.

In a hydraulic lift, the area of smaller piston is 5 cm^2. The weight

1.	In a hydraulic lift, the area of smaller piston is 5 cm^2. The weight raised by larger piston is 900 kgf, if a force of 150 kg fis applied on smaller piston. Calculate the area of larger piston.
Answer» <html><body><p></p>Solution :`a=<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a> <a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a>^(2) =5 xx 10^(-4) m^(2)` <br/> f=150kgf `=150 xx 9.8 N`<br/> `F=<a href="https://interviewquestions.tuteehub.com/tag/900-341675" style="font-weight:bold;" target="_blank" title="Click to know more about 900">900</a> xx 9.8 N` <br/> As `f/a=F/A` <br/> `(150 xx 9.8)/(5 xx 10^(-4)) =(900) xx 9.8)/(A))` <br/> Solving we get `A=30 xx 10^(-4) m^(2)`</body></html>