In a hydraulic press, the diameters of two pistons are 6 cm and 60 cm. The force exerted on the larger piston is n xx 7200 kg wt if 100 kg wt is placed on smaller piston. Find the value of n.

In a hydraulic press, the diameters of two pistons are 6 cm and 60 cm.

1.	In a hydraulic press, the diameters of two pistons are 6 cm and 60 cm. The force exerted on the larger piston is n xx 7200 kg wt if 100 kg wt is placed on smaller piston. Find the value of n.
Answer» Solution :`A_(1)=pi (5/2)^(2) cm^(2)=pi (2.5)^(2) xx 10^(-4) m^(2)` `A_(2)=pi (60/2)^(2) cm^(2)=pi (30^(2) xx 10^(-4) m^(2)` `F_(1)=100 kg WT` In hydraulic press `F_(2)/F_(1)=A_(2)/A_(1)` `F_(2)=F_(1) A_(2)/A_(1)=(100 xx pi (30)^(2) xx 10^(-4))/(pi (2.5)^(2) xx 10^(-4))` `=14400 kg wt`