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In a hydrogen atom , in transition of electron a photon of energy 2.55 eV is emitted , then the change in wavelenghtof the eletron is |
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Answer» `3.32Å` `4 to 2` `lambda_(4)=(2pir_(4))/(4)""lambda_(2)=(2pir_(2))/(2)` `lambda_(4)lambda_(2P)=2pi[(0.529(4)^(2))/(1xx4)-(0.529(2)^(2))/(2)]` =`2pi(0.529)(2)` `=4pir_(1)`=`6.64 Å` |
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