1.

In a hydrogen atom , in transition of electron a photon of energy 2.55 eV is emitted , then the change in wavelenghtof the eletron is

Answer»

`3.32Å`
`6.64Å`
`9.97Å`
NONE of these

SOLUTION :`2pir_(n)=nlambda`
`4 to 2`
`lambda_(4)=(2pir_(4))/(4)""lambda_(2)=(2pir_(2))/(2)`
`lambda_(4)lambda_(2P)=2pi[(0.529(4)^(2))/(1xx4)-(0.529(2)^(2))/(2)]`
=`2pi(0.529)(2)`
`=4pir_(1)`=`6.64 Å`


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