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In a hydrogen atom, the distance between the electron and proton is `2.5 xx 10^(-11)m`. The electricl force of attraction between then will beA. `6.3xx10^(-8)N`B. `8.2xx10^(-8)N`C. `9.6xx10^(-8)N`D. `12.2xx10^(-8)N` |
Answer» Correct Answer - B `F=1/(4piin_(0))xx(q_(1)q_(2))/r^(2)` `=(9xx10^(9)xx1.6xx1.6xx10^(-38))/((5.3xx10^(-11))^(2))` `=8.2xx10^(-8)N` |
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