. In a hydrogen atom, the electrons fall from fifth orbit to the secon

1.	. In a hydrogen atom, the electrons fall from fifth orbit to the second orbit. Calculate the frequency and wavelength of the radiation emitted in this radiation. (Value of R = 109714 cm-1).
Answer» Answer:WAVELENGTH of photon emitted DUE to electronic transition from n1=3 to n2=2 of HYDROGEN atom λ1=R(n221−n121) ∴ λ1=R(221−321) ⟹λ=5R36 Thus FREQUENCY of photon ν=λC=365RC

. In a hydrogen atom, the electrons fall from fifth orbit to the second orbit. Calculate the frequency and wavelength of the radiation emitted in this radiation. (Value of R = 109714 cm-1).

Answer»

Answer:WAVELENGTH of photon emitted DUE to electronic transition from n1=3 to n2=2 of HYDROGEN atom

λ1=R(n221−n121)

∴ λ1=R(221−321) ⟹λ=5R36

Thus FREQUENCY of photon ν=λC=365RC