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In a hydrogen atom.the energy of an electron in first Bohr's orbit is 13.12xx10^(5)J mol^(-1).What is th energy required for its excitation to Bohr's second orbit? |
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Answer» Solution :`E_n=-(2pi^(2)m_e^(4))/(n^(2)h^(2)` When`n=1,E_1=-(2pi^(2)m_e^(4))/((1)^(2)h^(2))=-13.12xx10^(5)J MOL^(-1)` When`n=2,E_2=-(2pi^(2)m_(E)^(4))/((2)^(2h^(2)))=-(13.12xx10^(5))/(4)J mol^(-1)`= =`3.28xx10^(5)J mol^(-1)` The energy required for the excitation is: `/_\E=E_2-E_1=(-3.28xx10^(5))-(-13.12xx10^(5))=9.84xx10^(5)Jmol^(-1)` |
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