In a hypothetical situation, the density of earth becomes three times that of its original density, but its radius remains same. The acceleration due to gravity becomes : (take g = 10 m//s^(2) on the earth)

In a hypothetical situation, the density of earth becomes three times

1.	In a hypothetical situation, the density of earth becomes three times that of its original density, but its radius remains same. The acceleration due to gravity becomes : (take g = 10 m//s^(2) on the earth)
Answer» `20 m//s^(2)` `40 m//s^(2)` `30 m//s^(2)` `10 m//s^(2)` Solution :As `g = (GM)/(R^(2)) = (G.(4)/(3) pi R^(3) RHO)/(R^(2)) = (4)/(3) pi G rho R` if density is made thrice, then g will also become 3 TIMES, i.e., `10 xx 3 = 30 m//s^(2)`