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In a mixture of gases, the volume content of a gas is 0.06% at STP. Calculate the number of molecules of the gas in 1 L of the mixture.A. `1.613xx10^23`B. `6.023xx10^23`C. `1.61xx10^27`D. `1.61xx10^19`

Answer» Volume of gas in 1 L `=(0.06)/(100)=6xx10^(-4)` L
` =6xx10^(-4)` L
No. of molecules of `CO_2=nxxN_A`
`(6xx10^(-4))/(22.4)xx6.023xx10^23=1.61xx10^19`


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