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In a moleculte A - B, electronegativities of atom A and B are 2.0 and 4.0 respectively. Calculate the percent ionic character of A- B bond using (i) Pauling equation (ii) Hannay and Smith equation. |
Answer» (i) According to Pauling equation % ionic character = `18 (chi _(A) - chi_(B))^(1-4) = 18 (4 - 2)^(1-4) = 18 xx 2 ^(1-4) = x (say)` ` long x = log 18 + 1.4 log 2 = 1.2553 + 1.4 xx 0.3010 = 1.6767` x = Antilog 1 .` 6767 = 47. 50 %` (ii) According to Smith and Hannay equation ` %` ionic character = `16 (chi _(A) - chi_(B)) + 3.5 (chi_(A) - chi_(B))^(2) = 16 xx 2 + 3.5 xx 2^(2)` ` = 32 + 14 = 46 %` |
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