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In a `p-n` junction the depletion region is `400 nm` wide and electric field of `5 xx 10^(5) Vm^(-1)` exists in it. The minimum energy of a conduction electron, which can diffuse from n-side to the p-side is.A. `4 eV`B. `5 eV`C. `0.4 eV`D. `0.2 eV` |
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Answer» Correct Answer - D `W = Vq = Edq` `= 5 xx 10^(5) xx 400 xx 10^(-9) xx 1.6 xx 10^(-19) J` `= (5 xx 10^(5) xx 400 xx 10^(-9) xx 1.6 xx 10^(-19)J)/(1.6 xx 10^(-19))eV` `= 2000 X 10^(-4) eV = 0.2 eV`. |
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