In a p−n junction, the depletion region is 500 nm wide an electric field 8×105 Vm−1 exist in it. The minimum kinetic energy of a conduction electron which can diffuse from the n−side to the p−side is ____×10−2 eV.(e = Charge of electron)

In a p−n junction, the depletion region is 500 nm wide an electric f

1.	In a p−n junction, the depletion region is 500 nm wide an electric field 8×105 Vm−1 exist in it. The minimum kinetic energy of a conduction electron which can diffuse from the n−side to the p−side is ____×10−2 eV.(e = Charge of electron)
Answer» In a $p - n$ junction, the depletion region is $500 nm$ wide an electric field $8 \times 10^{5} {Vm}^{- 1}$ exist in it. The minimum kinetic energy of a conduction electron which can diffuse from the $n -$ side to the $p -$ side is ____ $\times 10^{- 2} eV .$ $(e = Charge of electron)$

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In a p−n junction, the depletion region is 500 nm wide an electric field 8×105 Vm−1 exist in it. The minimum kinetic energy of a conduction electron which can diffuse from the n−side to the p−side is ____×10−2 eV.(e = Charge of electron)

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