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In a `P-N-P` transistor, the collector current is `10 mA`. If `90%` of the holes reach the collector, then emitter current will be :A. `13 mA`B. `12 mA`C. `11 mA`D. `10 mA` |
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Answer» Correct Answer - C `I_(C)=(90)/(100)I_(E) rArr I_(E)=(10)/(9) I_(C)`. |
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