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InterviewSolution
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In a parallel plate capacitor with air between the plates, each plate has an area of 5 × 103 m2 and the separation between the plates is 2.5 mm. (i) Calculate the capacitance of the capacitor. (ii) If this capacitor is connected to 100 V supply, what would be the charge on each plate? (iii) How would charge on the plates be affected, if a 2.5 mm thick mica sheet of K = 8 is inserted between the plates while the voltage supply remains connected? |
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Answer» Here, A = 5 × 10–3 m2, d = 2.5 mm = 2.5 × 10–3 m (i) Capacitance, C = ε0A/d = (8.85 x 10-12 x 5 x 10-3/2.5 x 10-3) = 17.7 x 10-12 F (ii) Charge, Q = CV = 17.7 x 10-12 x 100 C = 17.7 x 10-10 C (iii) New charge, Q’ = KQ = 8 x 17.7 x 10-10 C = 141.6 x 10-10 C |
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