1.

In a parallel plate capacitor with air between the plates, each plate has an area of 6 × 10–3 m2 and the separation between the plates is 3 mm. (i) Calculate the capacitance of the capacitor. (ii) If this capacitor is connected to 100 V supply, what would be the charge on each plate? (iii) How would charge on the plates be affected, if a 3 mm thick mica sheet of K = 6 is inserted between the plates while the voltage supply remains connected?

Answer»

Here, A = 6 × 10–3 m2, d = 3 mm = 3 × 10–3 m

(i) Capacitance, C = ε0A/d = (8.85 x 10-12 x 6 x 10-3/3 x 10-3) = 17.7 x 10-12 F

(ii) Charge, Q = CV = 17.7 x 10-12 x 100C = 17.7 x 10-10C

(iii) New charge, Q’ = KQ =6 x 17.7 x 10-10 C =106.2 x10-10 C



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