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in a parallelogram ABCD. AN and CP are perpendiculas to BD. show that(i) ADN is similar to CBP. (ii)AN=CP |
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Answer» Solution:In △ADN and △CBP AD=CB (opposite side of parallelogram)∠AND=∠CPB (each 90 ∘ )∠ADN=∠PBC (AD∥BC,BD is transversal) (alternate INTERIOR angles) 1. THEREFORE,△ADN=△CBP (ASA rule)2. AN=CP (By CPCT) Hence proved. |
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