1.

In a parallelogram ABCD, any point E is taken on the side BC. AE and DC when produced meet at a point M. Prove thatar(∆ADM) = ar(ABMC)

Answer» In a parallelogram ABCD, any point E is taken on the side BC. AE and DC when produced meet at a point M. Prove that

ar(∆ADM) = ar(ABMC)


Discussion

No Comment Found

Related InterviewSolutions