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In a parallelogram ABCD, any point E is taken on the side BC. AE and DC when produced meet at a point M. Prove thatar(∆ADM) = ar(ABMC) |
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Answer» In a parallelogram ABCD, any point E is taken on the side BC. AE and DC when produced meet at a point M. Prove that ar(∆ADM) = ar(ABMC) |
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