In a parallelogram PQRS if angle p=3x-5angleQ=2X+50 find x

1.	In a parallelogram PQRS if angle p=3x-5angleQ=2X+50 find x
Answer» Similar as (Q=2x+15):{tex}\\angle P+\\angle Q=180^{\\circ}{/tex}\xa0(Angles on the same side of a transversal are supplementary){tex}\\Rightarrow \\ 3 x-5+2 x+15=180^{\\circ}{/tex}5x + 10 = 180o{tex}\\Rightarrow{/tex}\xa05x + 170o\xa0{tex}\\Rightarrow{/tex}\xa0x = 34o 3x-5+2x+50=180 (angle on the same side of a transversal are supplementary)5x+45=1805x=135X= 27

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