1.

In a particular system, the unit of length, mass and time are chosen to be 10 cm, 10 g and 0.1 s respectively. The unit of force in this system will be equivalent to

Answer»

0.1 N
1N
10N
100N

Solution :
The dimensional formula of force is `[MLT^(-2)]`
`:. a= 1, b= 1, c=-2`
`n_(2)= n_(1)[(M_(1))/(M_(2))]^(a)[(L_(1))/(L_(2))]^(b)[(T_(1))/(T_(2))]^(c)= 1[(10KG)/(1kg)]^(1)[(10cm)/(1m)^(1)][(0.1s)/(1s)]^(-2)`
`= 1((10^(-2)kg)/(1kg))^(1)((10^(-1)m)/(1m))^(1)((0.1s)/(1s))^(-2)`
`= ( 1XX 10^(-2) xx10^(-1))/(10^(-2))= 10^(-1)= 0.1 `
hence, the unit of force in a GIVEN system will be equivalent to 0.1 N.


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