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In a particular system, the unit of length, mass and time are chosen to be 10 cm, 10 g and 0.1 s respectively. The unit of force in this system will be equivalent to |
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Answer» 0.1 N The dimensional formula of force is `[MLT^(-2)]` `:. a= 1, b= 1, c=-2` `n_(2)= n_(1)[(M_(1))/(M_(2))]^(a)[(L_(1))/(L_(2))]^(b)[(T_(1))/(T_(2))]^(c)= 1[(10KG)/(1kg)]^(1)[(10cm)/(1m)^(1)][(0.1s)/(1s)]^(-2)` `= 1((10^(-2)kg)/(1kg))^(1)((10^(-1)m)/(1m))^(1)((0.1s)/(1s))^(-2)` `= ( 1XX 10^(-2) xx10^(-1))/(10^(-2))= 10^(-1)= 0.1 ` hence, the unit of force in a GIVEN system will be equivalent to 0.1 N. |
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