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In a photoelectric experiment, kinetic energy of photoelectron is 18.2 × 10^-19 J. the wavelength of incident light is X ×10^-8m , if work function of metal is 1eV, then value of X is ____.(planks constant= 6.6×10^-34Js and 1eV =1.6×10^-19J)please help me out |
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Answer» Energy of incident RADIATION is E= λ hc = 3×10 −7
6.6×10 −34 ×3×10 8
=6.6×10 −19 J. Also, work function is ϕ=2×1.6×10 −19 J=3.2×10 −19 J. Hence, maximum kinetic energy of emitted PHOTO electrons will be 6.6×10 −19 J−3.2×10 −19 J=3.4×10 −19 J Explanation: @maahiarora401 |
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