In a picnic with 20 persons where 6 chocolates will be given to the top 8 children(the chocolates are distinct: first, second). How many ways can this be done?(a) ^18C6(b) ^20P6(c) ^25C4 * 6!(d) ^19P5I have been asked this question in a job interview.The above asked question is from Counting topic in division Counting of Discrete Mathematics

In a picnic with 20 persons where 6 chocolates will be given to the to

1.	In a picnic with 20 persons where 6 chocolates will be given to the top 8 children(the chocolates are distinct: first, second). How many ways can this be done?(a) ^18C6(b) ^20P6(c) ^25C4 * 6!(d) ^19P5I have been asked this question in a job interview.The above asked question is from Counting topic in division Counting of Discrete Mathematics
Answer» Right ANSWER is (B) ^20P6 To elaborate: This is a permutation problem since the chocolates are distinct. The answer is P(20, 6) -> the number of ways to arrange 20 things taken 6 at a TIME -> which is \(\frac{20!}{(20-6)!}\) = 2019181716*15.

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