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In a plane e.m. wave of frequency `1.5xx10^12Hz`, the amplitude fo the magnetic field is `6.0xx10^-6T`. (a) Calculate the amplitude of the electric field. (b) What is the total average energy density of the e.m. wave? |
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Answer» Correct Answer - (a) `1.8xx10^3 Vm^-1 (b) 1.4xx10^-5J//m^-3` Here, `v=1.5xx10^(12)Hz, B_0=6.0xx10^-6T` (a) Amplitude of electric field, `E_0=CB_0=(3xx10^8)xx(6.0xx10^-6)` `=1.8xx10^3Vm^-1` (b) Total average energy density is `U_(av)=1/2in_0E_0^2=1/2(8.85xx10^(-12))xx(1.8xx10^3)^2` `=1.4xx10^-5Jm^-3` |
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