In a `PNP` transistor working as common-base amplifier, current gain is `0.96` and current is `7.2 mA`. The base current isA. `0.4 mA`B. `0.2 mA`C. `0.29 mA`D. `0.35 mA`

In a `PNP` transistor working as common-base amplifier, current gain i

1.	In a `PNP` transistor working as common-base amplifier, current gain is `0.96` and current is `7.2 mA`. The base current isA. `0.4 mA`B. `0.2 mA`C. `0.29 mA`D. `0.35 mA`
Answer» Correct Answer - C `alpha=(i_(c))/(i_(e)) =0.96` and `i_(e)=7.2 mA` `i_(c)=0.96xxi_(e)=0.96xx7.2=6.91mA` `:. i_(e)=i_(c)+i_(b) implies 7.2=6.91+i_(b) implies i_(b)=0.29 mA`.

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In a `PNP` transistor working as common-base amplifier, current gain is `0.96` and current is `7.2 mA`. The base current isA. `0.4 mA`B. `0.2 mA`C. `0.29 mA`D. `0.35 mA`

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