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In a potentiometer experiment it is found that no current passes through the galvanometer when the terminals of the cell are connected across `0.52 m` of the potentiometer wire. If the cell is shunted by a resistance of `5Omega` balance is obtained when the cell connected across` 0.4m` of the wire. Find the internal resistance of the cell.A. `0.5 Omega`B. `1 Omega`C. `1.5 Omega`D. `2 Omega`

Answer» Correct Answer - C
(c ) `r = [(l_(1))/(l_(2)) - 1] = 5 [(0.52)/(0.4) - 1] = 5 [1.3 - 1] = 1.5 Omega`


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