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In a potentiometer experiment, the balancing length is found to be 1.8 m for a cell of e.m.f. 1.5 V. What is the balancing length for a cell of e.m.f. 1 V ?A. 1.2 mB. 0.5mC. 2.2mD. 0.2

Answer» Correct Answer - A
`(E_(2))/(E_(1))=(l_(2))/(l_(1)) " " :.l_(2)=(1xx1.8)/(1.5)=1.2m`


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