In a process, 701 J of heat is absorbed by a system and 394 J of work is done by the system. What is the change in internal energy for the process ?

In a process, 701 J of heat is absorbed by a system and 394 J of work

1.	In a process, 701 J of heat is absorbed by a system and 394 J of work is done by the system. What is the change in internal energy for the process ?
Answer» Solution :As per the FIRST law of thermodynamics `Delta U= Q+w` `= 701 + (-394)` `= 307` J Where `q= +701` J `w=-394` J `Delta U = (?)`