In a process, 701 J of heat is absorbed by a system and 394 J of work is done by the system. What is the change in internal energy for the process?

In a process, 701 J of heat is absorbed by a system and 394 J of work

1.	In a process, 701 J of heat is absorbed by a system and 394 J of work is done by the system. What is the change in internal energy for the process?
Answer» Solution :Since HEAT is absorbed, it is GIVEN POSITIVE sign,i.e. q=701J Since WORK is done by the system, it is given negative sign i.e. w=-394J `therefore DeltaU=q+w=701-394=+307 J`