In a process, 701 J of heat is absorbed by a system and 394 J of work is done by the system.What is the change in internal energy for the process?

In a process, 701 J of heat is absorbed by a system and 394 J of work

1.	In a process, 701 J of heat is absorbed by a system and 394 J of work is done by the system.What is the change in internal energy for the process?
Answer» Solution :Heat ABSORBED by the system = 701 J or q = 701 J Work done by the system = 394 J or w = -394 J According to first LAW of THERMODYNAMICS `DeltaU = q + w` `DeltaU = 701 -394 = 307 J`.