In a quadrilateral ABCD, ∠B = ∠90°, \(AD^2=AB^2+BC^2+CD^2\) pr – InterviewSolution

InterviewSolution

1.

In a quadrilateral ABCD, ∠B = ∠90°, \(AD^2=AB^2+BC^2+CD^2\) prove that ∠ACD = 90°

Answer»

We have

∠B = 90° and

AD² = AB² + BC² + CD² (Given)

But AB² + BC² = AC²

AD² = AC² + CD²

By converse of by Pythagoras

∠ACD = 90°

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