1.

In a quality control analysis for sulphur impurity 5.6g steel sample was burnt in a stream of oxygen and sulphur was converted into SO_(2) gas. The SO_(2) was then oxidized to sulphate by using H_(2)O_(2) solution to which has been added 30 mL of 0.04M NaOH. The equation ofthe reaction is: SO_(2(g)) +H_(2)O_((aq.))+2OH_((aq.))^(-)to SO_(4(aq.))^(2-) +2H_(2)O_((l)) 22.48mL of 0.024M HCI was required to neutralize the base remaining after oxidation reaction. Calculate % sulphur in given sample.

Answer»


ANSWER :`0.1875%`


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