In a radioactive sample, the fraction of initial number of redioactive nuclie, which remains undecayed after n mean lives isA. `(1)/(e^(n))`B. `e^(n)`C. `1-(1)/(e^(n))`D. `((1)/(e-1))^(n)`

In a radioactive sample, the fraction of initial number of redioactive

1.	In a radioactive sample, the fraction of initial number of redioactive nuclie, which remains undecayed after n mean lives isA. `(1)/(e^(n))`B. `e^(n)`C. `1-(1)/(e^(n))`D. `((1)/(e-1))^(n)`
Answer» Correct Answer - A `(N)/(N_(0))=e^(-lamda((n)/(lamda)))=(1)/(e^(n))" "(therefore"mean life", t=(1)/(lamda))`

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In a radioactive sample, the fraction of initial number of redioactive nuclie, which remains undecayed after n mean lives isA. `(1)/(e^(n))`B. `e^(n)`C. `1-(1)/(e^(n))`D. `((1)/(e-1))^(n)`

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