In a reaction, 5.3 gram of sodium carbonate reacted with 6 gram of 2.2

1.	In a reaction, 5.3 gram of sodium carbonate reacted with 6 gram of 2.2 gram of carbon dioxide, o.9 gram water and 8.2 gram of sodium ethanoate. show that these observations are in agreement with the law of conservation os mass.sodium carbonate + ethanoic acid➡️ sodium ethanoate + carbon dioxide + water
Answer» ☆ MASS of sodium carbonate = 5.3 g (given) ☆ Mass of ETHANOIC acid = 6 g (given) ☆ Mass of sodium ethanoate = 8.2 g (given) ☆ Mass of Carbon dioxide = 2.2 g (given) ☆ Mass of water = 0.9 g (given) Now, total mass before the reaction = (5.3 + 6) g = 11 . 3 g And, total mass after the reaction = (8.2 + 2.2 + 0.9 ) g = 11.3 g total mass before the reaction = total mass after the reaction. $\bigstar$ Hence, the given observations are in agreement with the LAW of conservation of mass. *mark* me as *brainliest*

In a reaction, 5.3 gram of sodium carbonate reacted with 6 gram of 2.2 gram of carbon dioxide, o.9 gram water and 8.2 gram of sodium ethanoate. show that these observations are in agreement with the law of conservation os mass.sodium carbonate + ethanoic acid➡️ sodium ethanoate + carbon dioxide + water

Answer»

☆ MASS of sodium carbonate = 5.3 g (given)

☆ Mass of ETHANOIC acid = 6 g (given)

☆ Mass of sodium ethanoate = 8.2 g (given)

☆ Mass of Carbon dioxide = 2.2 g (given)

☆ Mass of water = 0.9 g (given)

Now, total mass before the reaction = (5.3 + 6) g

= 11 . 3 g

And, total mass after the reaction = (8.2 + 2.2 + 0.9 ) g

= 11.3 g

total mass before the reaction = total mass after the reaction.

$\bigstar$ Hence, the given observations are in agreement with the LAW of conservation of mass.

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