1.

In a reaction , A+ 2 B hArr 2 C, 2.0mole of 'A' 3.0 mole of 'B' and 2.0 mole of 'C' are placed in a 2.0 L flask and the equilibrium concentration of 'C' is 0.5 mole/L. The equilibrium constant (K) for the reaction is

Answer»

`0.073`
`0.147`
`0.05`
`0.026`

Solution :` {:(,A,+,2B,hArr,2C),("Intial conc.",1 "MOL "L^(-1),,1.5 " mol "L^(-1),,1 " mol "L^(-1)),("At eqm.",(1+0.25),,(1.5 + 0.5),,0.5),(,=1.25,,=2.0,," mol "L^(-1)),(," mol"L^(-1),," mol"L^(-1),,):}`
`K= (0.5)^(2)/(1.25 xx (2.0)^(2)) = 0.05`
Note that 0.5 mol `L^(-1)` of C has decomposed to produce 0.25 mol of A and .5 mol of B.


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