In a reaction at equilibrium, x' mole of the reactant 'A' decompose to give I mole of C and D. It has been found that the fraction of A decomposed at equilibrium is independent of intial concentration of A. Find the value of x.

In a reaction at equilibrium, x' mole of the reactant 'A' decompose to

1.	In a reaction at equilibrium, x' mole of the reactant 'A' decompose to give I mole of C and D. It has been found that the fraction of A decomposed at equilibrium is independent of intial concentration of A. Find the value of x.
Answer» Solution :`IXA harr D+C` `a(1-alpha), (a alpha)/(x), (a alpha)/(x)` `K_(c)=(a^(2)alpha^(2))/(V^(2)x^(2)[(a(1-alpha))/(V)]^(x))=(alpha^(2)a^(2-x))/(x^(2)(1-alpha)x 2-x)` `alpha` INDEPENDENT of a =2-x=0 `IMPLIES` x=2