In a reaction, `Cr_(2)O_(7)^(2-)` is reduced to `Cr^(3+)`. What is concentration of `0.1M K_(2)Cr_(2)O_(7)` in equivalent per litre? `Cr_(2)O_(7)^(2-)+14H^(+)+6erarr2Cr^(3+)+7H_(2)O`

In a reaction, `Cr_(2)O_(7)^(2-)` is reduced to `Cr^(3+)`. What is con

1.	In a reaction, `Cr_(2)O_(7)^(2-)` is reduced to `Cr^(3+)`. What is concentration of `0.1M K_(2)Cr_(2)O_(7)` in equivalent per litre? `Cr_(2)O_(7)^(2-)+14H^(+)+6erarr2Cr^(3+)+7H_(2)O`
Answer» `N = M xx " valence factor"` `therefore N = 0.1 xx 6` `(Cr_(2)^(6+) + 6erarr 2Cr_(3+))` or `N_(K_(2)Cr_(2)O_(7)) = 0.6 N`

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In a reaction, `Cr_(2)O_(7)^(2-)` is reduced to `Cr^(3+)`. What is concentration of `0.1M K_(2)Cr_(2)O_(7)` in equivalent per litre? `Cr_(2)O_(7)^(2-)+14H^(+)+6erarr2Cr^(3+)+7H_(2)O`

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